Unzip a File to Memory in Scala

Recently I had some trouble unzipping a file in Scala.  After combing through many different StackOverflow threads I eventually worked out this solution:

def unzip(path: String): Map[String, Array[Byte]] = {
val zipFile = new ZipFile(path)
zipFile.entries().asScala
.filter(!_.isDirectory)
.map { entry =>
val in = zipFile.getInputStream(entry)
val out = new ByteArrayOutputStream
IOUtils.copy(in, out)
IOUtils.closeQuietly(in)
IOUtils.closeQuietly(out)
entry.getName -> out.toByteArray
} toMap
}