Recently I had some trouble unzipping a file in Scala. After combing through many different StackOverflow threads I eventually worked out this solution:
def unzip(path: String): Map[String, Array[Byte]] = { val zipFile = new ZipFile(path) zipFile.entries().asScala .filter(!_.isDirectory) .map { entry => val in = zipFile.getInputStream(entry) val out = new ByteArrayOutputStream IOUtils.copy(in, out) IOUtils.closeQuietly(in) IOUtils.closeQuietly(out) entry.getName -> out.toByteArray } toMap }